NOMA

x = optimvar( 'x' , 2, 1); p = optimproblem(); p.Objective = x(1)^2+x(2)^2; p.Constraints.C = x(1) + x(2) + 3 ==0; [sol, fval, exitflag, output, lambda] = solve(p); sol.x lambda.Constraints

   Design a basic OFDM system utilizing an IFFT as the OFDM modulator and an FFT as the OFDM demodulator. I am showing you a figure by which we can under the basic fundamentals of OFDM. OFDM Modulation with IFFT Step-1 Firstly, define the number of bits. it will be in the power of 2.  which means the QAM signal's length is also a power of 2. The  ifft  and  fft  functions are significantly faster for signals of certain lengths, including those whose length is a power of 2. Syntax-   numBits = 32768; Step-2 Define the modulation order Syntax-  modOrder = 16; % for 16-QAM Step-3 Generate the random signal Syntax-  srcBits = randi([0,1],numBits,1); Step-4 Modulate the Signal (Here we are doing QAM Modulation) Syntax-  qamModOut = qammod(srcBits,modOrder, "InputType" , "bit" , "UnitAveragePower" ,true); Step-5 Calculate the Inverse Fast Fourier Transform (IFFT) of the 16-QAM signal. Syntax- ofdmModOut = ifft(qamModOut) Addition of No...